Integrand size = 23, antiderivative size = 152 \[ \int \frac {(d+i c d x)^2 (a+b \arctan (c x))}{x^3} \, dx=-\frac {b c d^2}{2 x}-\frac {1}{2} b c^2 d^2 \arctan (c x)-\frac {d^2 (a+b \arctan (c x))}{2 x^2}-\frac {2 i c d^2 (a+b \arctan (c x))}{x}-a c^2 d^2 \log (x)+2 i b c^2 d^2 \log (x)-i b c^2 d^2 \log \left (1+c^2 x^2\right )-\frac {1}{2} i b c^2 d^2 \operatorname {PolyLog}(2,-i c x)+\frac {1}{2} i b c^2 d^2 \operatorname {PolyLog}(2,i c x) \]
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Time = 0.11 (sec) , antiderivative size = 152, normalized size of antiderivative = 1.00, number of steps used = 13, number of rules used = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.435, Rules used = {4996, 4946, 331, 209, 272, 36, 29, 31, 4940, 2438} \[ \int \frac {(d+i c d x)^2 (a+b \arctan (c x))}{x^3} \, dx=-\frac {d^2 (a+b \arctan (c x))}{2 x^2}-\frac {2 i c d^2 (a+b \arctan (c x))}{x}-a c^2 d^2 \log (x)-\frac {1}{2} b c^2 d^2 \arctan (c x)-\frac {1}{2} i b c^2 d^2 \operatorname {PolyLog}(2,-i c x)+\frac {1}{2} i b c^2 d^2 \operatorname {PolyLog}(2,i c x)-i b c^2 d^2 \log \left (c^2 x^2+1\right )+2 i b c^2 d^2 \log (x)-\frac {b c d^2}{2 x} \]
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Rule 29
Rule 31
Rule 36
Rule 209
Rule 272
Rule 331
Rule 2438
Rule 4940
Rule 4946
Rule 4996
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {d^2 (a+b \arctan (c x))}{x^3}+\frac {2 i c d^2 (a+b \arctan (c x))}{x^2}-\frac {c^2 d^2 (a+b \arctan (c x))}{x}\right ) \, dx \\ & = d^2 \int \frac {a+b \arctan (c x)}{x^3} \, dx+\left (2 i c d^2\right ) \int \frac {a+b \arctan (c x)}{x^2} \, dx-\left (c^2 d^2\right ) \int \frac {a+b \arctan (c x)}{x} \, dx \\ & = -\frac {d^2 (a+b \arctan (c x))}{2 x^2}-\frac {2 i c d^2 (a+b \arctan (c x))}{x}-a c^2 d^2 \log (x)+\frac {1}{2} \left (b c d^2\right ) \int \frac {1}{x^2 \left (1+c^2 x^2\right )} \, dx-\frac {1}{2} \left (i b c^2 d^2\right ) \int \frac {\log (1-i c x)}{x} \, dx+\frac {1}{2} \left (i b c^2 d^2\right ) \int \frac {\log (1+i c x)}{x} \, dx+\left (2 i b c^2 d^2\right ) \int \frac {1}{x \left (1+c^2 x^2\right )} \, dx \\ & = -\frac {b c d^2}{2 x}-\frac {d^2 (a+b \arctan (c x))}{2 x^2}-\frac {2 i c d^2 (a+b \arctan (c x))}{x}-a c^2 d^2 \log (x)-\frac {1}{2} i b c^2 d^2 \operatorname {PolyLog}(2,-i c x)+\frac {1}{2} i b c^2 d^2 \operatorname {PolyLog}(2,i c x)+\left (i b c^2 d^2\right ) \text {Subst}\left (\int \frac {1}{x \left (1+c^2 x\right )} \, dx,x,x^2\right )-\frac {1}{2} \left (b c^3 d^2\right ) \int \frac {1}{1+c^2 x^2} \, dx \\ & = -\frac {b c d^2}{2 x}-\frac {1}{2} b c^2 d^2 \arctan (c x)-\frac {d^2 (a+b \arctan (c x))}{2 x^2}-\frac {2 i c d^2 (a+b \arctan (c x))}{x}-a c^2 d^2 \log (x)-\frac {1}{2} i b c^2 d^2 \operatorname {PolyLog}(2,-i c x)+\frac {1}{2} i b c^2 d^2 \operatorname {PolyLog}(2,i c x)+\left (i b c^2 d^2\right ) \text {Subst}\left (\int \frac {1}{x} \, dx,x,x^2\right )-\left (i b c^4 d^2\right ) \text {Subst}\left (\int \frac {1}{1+c^2 x} \, dx,x,x^2\right ) \\ & = -\frac {b c d^2}{2 x}-\frac {1}{2} b c^2 d^2 \arctan (c x)-\frac {d^2 (a+b \arctan (c x))}{2 x^2}-\frac {2 i c d^2 (a+b \arctan (c x))}{x}-a c^2 d^2 \log (x)+2 i b c^2 d^2 \log (x)-i b c^2 d^2 \log \left (1+c^2 x^2\right )-\frac {1}{2} i b c^2 d^2 \operatorname {PolyLog}(2,-i c x)+\frac {1}{2} i b c^2 d^2 \operatorname {PolyLog}(2,i c x) \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 0.07 (sec) , antiderivative size = 139, normalized size of antiderivative = 0.91 \[ \int \frac {(d+i c d x)^2 (a+b \arctan (c x))}{x^3} \, dx=-\frac {d^2 \left (a+4 i a c x+b \arctan (c x)+4 i b c x \arctan (c x)+b c x \operatorname {Hypergeometric2F1}\left (-\frac {1}{2},1,\frac {1}{2},-c^2 x^2\right )+2 a c^2 x^2 \log (x)-4 i b c^2 x^2 \log (x)+2 i b c^2 x^2 \log \left (1+c^2 x^2\right )+i b c^2 x^2 \operatorname {PolyLog}(2,-i c x)-i b c^2 x^2 \operatorname {PolyLog}(2,i c x)\right )}{2 x^2} \]
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Time = 1.01 (sec) , antiderivative size = 157, normalized size of antiderivative = 1.03
method | result | size |
parts | \(a \,d^{2} \left (-\frac {1}{2 x^{2}}-c^{2} \ln \left (x \right )-\frac {2 i c}{x}\right )+b \,d^{2} c^{2} \left (-\arctan \left (c x \right ) \ln \left (c x \right )-\frac {2 i \arctan \left (c x \right )}{c x}-\frac {\arctan \left (c x \right )}{2 c^{2} x^{2}}-\frac {i \ln \left (c x \right ) \ln \left (i c x +1\right )}{2}+\frac {i \ln \left (c x \right ) \ln \left (-i c x +1\right )}{2}-\frac {i \operatorname {dilog}\left (i c x +1\right )}{2}+\frac {i \operatorname {dilog}\left (-i c x +1\right )}{2}-\frac {1}{2 c x}+2 i \ln \left (c x \right )-i \ln \left (c^{2} x^{2}+1\right )-\frac {\arctan \left (c x \right )}{2}\right )\) | \(157\) |
derivativedivides | \(c^{2} \left (a \,d^{2} \left (-\ln \left (c x \right )-\frac {2 i}{c x}-\frac {1}{2 c^{2} x^{2}}\right )+b \,d^{2} \left (-\arctan \left (c x \right ) \ln \left (c x \right )-\frac {2 i \arctan \left (c x \right )}{c x}-\frac {\arctan \left (c x \right )}{2 c^{2} x^{2}}-\frac {i \ln \left (c x \right ) \ln \left (i c x +1\right )}{2}+\frac {i \ln \left (c x \right ) \ln \left (-i c x +1\right )}{2}-\frac {i \operatorname {dilog}\left (i c x +1\right )}{2}+\frac {i \operatorname {dilog}\left (-i c x +1\right )}{2}-\frac {1}{2 c x}+2 i \ln \left (c x \right )-i \ln \left (c^{2} x^{2}+1\right )-\frac {\arctan \left (c x \right )}{2}\right )\right )\) | \(162\) |
default | \(c^{2} \left (a \,d^{2} \left (-\ln \left (c x \right )-\frac {2 i}{c x}-\frac {1}{2 c^{2} x^{2}}\right )+b \,d^{2} \left (-\arctan \left (c x \right ) \ln \left (c x \right )-\frac {2 i \arctan \left (c x \right )}{c x}-\frac {\arctan \left (c x \right )}{2 c^{2} x^{2}}-\frac {i \ln \left (c x \right ) \ln \left (i c x +1\right )}{2}+\frac {i \ln \left (c x \right ) \ln \left (-i c x +1\right )}{2}-\frac {i \operatorname {dilog}\left (i c x +1\right )}{2}+\frac {i \operatorname {dilog}\left (-i c x +1\right )}{2}-\frac {1}{2 c x}+2 i \ln \left (c x \right )-i \ln \left (c^{2} x^{2}+1\right )-\frac {\arctan \left (c x \right )}{2}\right )\right )\) | \(162\) |
risch | \(-\frac {i c^{2} b \,d^{2} \operatorname {dilog}\left (i c x +1\right )}{2}+\frac {3 i c^{2} b \,d^{2} \ln \left (i c x \right )}{4}-\frac {3 i c^{2} b \,d^{2} \ln \left (i c x +1\right )}{4}-\frac {5 b \,c^{2} d^{2} \arctan \left (c x \right )}{4}+\frac {c \,d^{2} b \ln \left (-i c x +1\right )}{x}-\frac {b c \,d^{2}}{2 x}+\frac {i b \,d^{2} \ln \left (i c x +1\right )}{4 x^{2}}-c^{2} d^{2} a \ln \left (-i c x \right )-\frac {i d^{2} b \ln \left (-i c x +1\right )}{4 x^{2}}-\frac {d^{2} a}{2 x^{2}}-\frac {2 i c \,d^{2} a}{x}+\frac {5 i c^{2} d^{2} b \ln \left (-i c x \right )}{4}-\frac {5 i b \,c^{2} d^{2} \ln \left (c^{2} x^{2}+1\right )}{8}-\frac {c b \,d^{2} \ln \left (i c x +1\right )}{x}+\frac {i c^{2} d^{2} b \operatorname {dilog}\left (-i c x +1\right )}{2}\) | \(237\) |
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\[ \int \frac {(d+i c d x)^2 (a+b \arctan (c x))}{x^3} \, dx=\int { \frac {{\left (i \, c d x + d\right )}^{2} {\left (b \arctan \left (c x\right ) + a\right )}}{x^{3}} \,d x } \]
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\[ \int \frac {(d+i c d x)^2 (a+b \arctan (c x))}{x^3} \, dx=- d^{2} \left (\int \left (- \frac {a}{x^{3}}\right )\, dx + \int \frac {a c^{2}}{x}\, dx + \int \left (- \frac {b \operatorname {atan}{\left (c x \right )}}{x^{3}}\right )\, dx + \int \left (- \frac {2 i a c}{x^{2}}\right )\, dx + \int \frac {b c^{2} \operatorname {atan}{\left (c x \right )}}{x}\, dx + \int \left (- \frac {2 i b c \operatorname {atan}{\left (c x \right )}}{x^{2}}\right )\, dx\right ) \]
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\[ \int \frac {(d+i c d x)^2 (a+b \arctan (c x))}{x^3} \, dx=\int { \frac {{\left (i \, c d x + d\right )}^{2} {\left (b \arctan \left (c x\right ) + a\right )}}{x^{3}} \,d x } \]
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\[ \int \frac {(d+i c d x)^2 (a+b \arctan (c x))}{x^3} \, dx=\int { \frac {{\left (i \, c d x + d\right )}^{2} {\left (b \arctan \left (c x\right ) + a\right )}}{x^{3}} \,d x } \]
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Time = 0.80 (sec) , antiderivative size = 161, normalized size of antiderivative = 1.06 \[ \int \frac {(d+i c d x)^2 (a+b \arctan (c x))}{x^3} \, dx=\left \{\begin {array}{cl} -\frac {a\,d^2}{2\,x^2} & \text {\ if\ \ }c=0\\ b\,d^2\,\left (c^2\,\ln \left (x\right )-\frac {c^2\,\ln \left (c^2\,x^2+1\right )}{2}\right )\,2{}\mathrm {i}+\frac {b\,c^2\,d^2\,{\mathrm {Li}}_{\mathrm {2}}\left (1-c\,x\,1{}\mathrm {i}\right )\,1{}\mathrm {i}}{2}-\frac {b\,c^2\,d^2\,{\mathrm {Li}}_{\mathrm {2}}\left (1+c\,x\,1{}\mathrm {i}\right )\,1{}\mathrm {i}}{2}-\frac {b\,d^2\,\left (c^3\,\mathrm {atan}\left (c\,x\right )+\frac {c^2}{x}\right )}{2\,c}-\frac {a\,d^2\,\left (2\,c^2\,x^2\,\ln \left (x\right )+1+c\,x\,4{}\mathrm {i}\right )}{2\,x^2}-\frac {b\,d^2\,\mathrm {atan}\left (c\,x\right )}{2\,x^2}-\frac {b\,c\,d^2\,\mathrm {atan}\left (c\,x\right )\,2{}\mathrm {i}}{x} & \text {\ if\ \ }c\neq 0 \end {array}\right . \]
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